Merhaba sitemde bu kodun olduğu tabloyu Popup olarak açmak istiyorum nasıl bir değişiklik yapmam gerekli

<?php do_action('wpdatatables_before_filtering_form', $this->getWpId()); ?>
<div class="wpDataTables wpDataTablesFilter wpDataTablesWrapper wdt-skin-<?php echo $this->getTableSkin(); ?> <?php echo apply_filters('wdt_add_class_to_filter_in_form_element', $this->getCSSClasses(), $this->getWpId()) ?>"
data-wpdatatable_id="<?php echo $this->getWpId(); ?>">
<div id="filterBox_<?php echo $this->getId() ?>" class="wpDataTableFilterBox">
<?php foreach ($this->getColumns() as $key => $dataColumn) { ?>
<?php
/** @var $dataColumn WDTColumn */
if ($dataColumn->getFilterType() != 'null') {
?>
<div class="wpDataTableFilterSection" id="<?php echo $this->getId() . '_' . $key . '_filter' ?>_sections">
<label><?php echo $dataColumn->getFilterLabel() ? $dataColumn->getFilterLabel() : $dataColumn->getTitle() ?>:</label>
<div id="<?php echo $this->getId() . '_' . $key . '_filter' ?>"></div>
</div>
<?php } ?>
<?php }
if ($this->isClearFilters()) { ?>
<div class="wpDataTableFilterSection" id="wdt-clear-filters-button-block">
<button class="button btn wdt-clear-filters-button" data-table_id = <?php echo $this->getId() ?>><?php _e('Clear filters', 'wpdatatables'); ?></button>
</div>
<?php } ?>
<?php
if (isset($this->showSearchFiltersButton) && isset($this->disableSearchFiltersButton)) {
do_action('wpdatatables_filtering_form_search_button', $this->showSearchFiltersButton, $this->disableSearchFiltersButton);
}
?>
</div>
</div>
<?php do_action('wpdatatables_after_filtering_form', $this->getWpId()); ?>