Bu veriyi nasil yazdirabilirim ?

16-10-2021, 15:23:28

<form action="index.php" method="post">
    search <input type="text" name="veri" id="veri">
    <br>
<input type="submit" value="Gonder">
    
    </form>


<?php



if ($_POST['veri']) 
{
 

   $veri = $_POST['veri'];



   $curl = curl_init();

   curl_setopt_array($curl, [
       CURLOPT_URL => "https://google-search3.p.rapidapi.com/api/v1/search/q=".$veri."&num=1",
       CURLOPT_RETURNTRANSFER => true,
       CURLOPT_FOLLOWLOCATION => true,
       CURLOPT_ENCODING => "",
       CURLOPT_MAXREDIRS => 10,
       CURLOPT_TIMEOUT => 30,
       CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
       CURLOPT_CUSTOMREQUEST => "GET",
       CURLOPT_HTTPHEADER => [
           "x-rapidapi-host: google-search3.p.rapidapi.com",
           "x-rapidapi-key: xxxxx",
           "x-user-agent: desktop"
       ],
   ]);
   
   $response = curl_exec($curl);
   $err = curl_error($curl);
   
   curl_close($curl);
   
   if ($err) {
       echo "cURL Error #:" . $err;
   } else {
    
echo "<pre>";

print_r($response);

echo "</pre>";





   }

   



}




?>

Veri Su sekilde Donuyor

{"results":[{"title":"Google","link":"https://www.google.com/","description":"Search the world's information, including webpages, images, videos and more. Google has many special features to help you find exactly what you're looking ...‎Images · ‎Account · ‎Google Scholar · ‎Google Contacts","additional_links":[{"text":"Googlehttps://www.google.com","href":"https://www.google.com/"},{"text":"キャッシュ","href":"https://webcache.googleusercontent.com/search?q=cache:y14FcUQOGl4J:https://www.google.com/+&cd=1&hl=ja&ct=clnk&gl=jp"},{"text":"Images","hre f":"https://www.google.com/imghp?hl=en"},{"text":"Account","href":"https://www.google.com/account/about/"},{"text":"Google Scholar","href":"https://scholar.google.com/"},{"text":"Google Contacts","href":"https://contacts.google.com/"}],"cite":{}}],"image_results":[],"total":9410000000,"answers":[],"ts":2.6249501705169678}

Ben buradan sadece assagidaki kismi almak istiyorum yani href anahtarinin dondurdugu link lazim sadece.

"href":"https://www.google.com/"

16-10-2021, 15:33:37

#2

profweb

$json = json_decode($response);
foreach($json->results as $item) {
    echo $item->link . "\n";
}

16-10-2021, 15:35:34

#3

kayazade

profweb adlı üyeden alıntı: mesajı görüntüle

$json = json_decode($response);
foreach($json->results as $item) {
    echo $item->link . "\n";
}

Hocam ya cok tesekkur ederim hayatimi kurtardin