
F hücresinde bir kontrol yaptırmam gerek (bu hücreye ürün kodları geliyor)
eğer F hücresine veri gelmiyorsa o satırı bulunduğu satırı göstermemem gerke. şuan ben Not Found basabildim ama satırı göstermemem gerekli. Yardımcı olabilirseniz sevinirim.
<table id="table2" cellspacing="0" width="100%"><thead><tr><th></th><th>RELATED PRODUCTS</th><th>PRODUCT DESCRIPTION</th><th>ADD</th><th>QUANTITY</th></tr>
</thead>
<tbody>
<?php
$id = "";
$veri = array_unique($veri);
$say=count($veri); for($x=3;$x<$say;$x++){$yeni[]=$veri[$x]; }
foreach ($yeni as $keyX => $valueX) { $id = str_replace(".", "", $valueX[A]);
if ($valueX[B]!=$product) {
continue;
}
?>
<tr>
<td style="text-align: center;">
<a class="zoom" data-pretty="prettyPhoto" href="/images/requestquote/<?php if($valueX[F]!="") echo $valueX[F] ; else echo "NOT FOUND"; ?>_big.png">
<img src="/images/requestquote/<?php if($valueX[F]!="") echo $valueX[F] ; else echo "NOT FOUND"; ?>_small.png" alt="" style="width:78px;height:60px" onerror="imgError(this);" class="image animated fadeInDown">
</a>
</td>
<td style="text-align: center;">
<?php if($valueX[F]!="") echo $valueX[F] ; else echo "NOT FOUND"; ?>
</td>
<td style="text-align: center;">
<?php if($valueX[D]!="") echo $valueX[D] ; else echo "NOT FOUND"; ?>
</td>
<td style="text-align: center;">
<input name="check_list[]" value=" <?php if($valueX[F]!="") echo $valueX[F] ; else echo "NOT FOUND"; ?>" type="checkbox">
</td>
<td style="text-align: center;">
<input type="text" name="quantity[]" id="quantity" style="width:45px">
</td>
</tr>
<?php } ?>
</tbody>
</table>
teşekkür ederim hocam