<?
mysql_connect($hostname, $username, $password);
mysql_select_db($database);
header('Content-type: text/xml');
echo '<?xml version="1.0" encoding="utf-8"?>';
echo '<govde>';
$sorgu = mysql_query("SELECT * FROM site_news WHERE id='1'");
while ($goster = mysql_fetch_array($sorgu)) {
echo '<icerik>'.$goster['news_news'].'</icerik>';
}
echo '</govde>';
?>
aldığım hata aşağıda sanki
while ($goster = mysql_fetch_array($sorgu)) { burada bir sorun var gibi
<?xml version="1.0" encoding="utf-8" ?>
- <govde>
<br />
<b>Warning</b>
: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in
<b>/site/public_html/deneme/xml/haber1.php</b>
on line
<b>17</b>
<br />
</govde>