Php ile foreach döngüsünden gelen menülere nasıl active class'ı verebilirim.
Bu şekilde tüm sayfaları mı kontrol edebiliyorum, ayrıca admin panelinden üst menü elemanlarının tutulduğu tablo mevcut.
if(isset($_GET['sayfa'])){
$page = $_GET['sayfa'];
switch($s){
case 'contact';
require_once("includes/contact");
break;
case 'about';
require_once("includes/about.php");
break;
case 'blog';
require_once("includes/blog.php");
break;
}Foreach döngü bu şekilde,
<?php foreach ($mainMenu as $menu1) {
$altMenu = $db->prepare("select * from header_menu where ust_id=:ust_id and dil=:dil and durum=:durum order by sira asc ");
$altMenu->execute(array(
'ust_id' => $menu1['id'],
'dil' => $_SESSION['dil'],
'durum' => '1'
));
?>
<li class="<?php if ($altMenu->rowCount() > '0') {
echo 'dropdown_menu';
} ?>">
<a <?php if ($menu1['url'] == !null) { ?>href="<?= $menu1['url'] ?>" <?php } else { ?>href="javascript:void(0" <?php } ?>><?= $menu1['baslik'] ?></a>
<?php if ($altMenu->rowCount() > '0') { ?>
<i class="caret_down"></i>
<?php } ?>
<?php if ($altMenu->rowCount() > '0') { ?>
<ul class="sub-menu">
<?php foreach ($altMenu as $menu2) {
$ucuncuMenu = $db->prepare("select * from header_menu where ust_id=:ust_id and dil=:dil and durum=:durum order by sira asc ");
$ucuncuMenu->execute(array(
'ust_id' => $menu2['id'],
'dil' => $_SESSION['dil'],
'durum' => '1'
));
?>
<li>
<a href="<?= $menu2['url'] ?>">
<?= $menu2['baslik'] ?>
<?php if ($ucuncuMenu->rowCount() > '0') { ?>
<i class="fa fa-angle-right" aria-hidden="true"></i>
<?php } ?>
</a>
<?php if ($ucuncuMenu->rowCount() > '0') { ?>
<ul class="third-level-menu">
<?php foreach ($ucuncuMenu as $menu3) { ?>
<li>
<a href="<?= $menu3['url'] ?>">
<p>
<?= $menu3['baslik'] ?>
</p>
</a>
</li>
<?php } ?>
</ul>
<?php } ?>
</li>
<?php } ?>
</ul>
<?php } ?>
</li>
<?php } ?> 