PHP sayfanın altında -> Page generated in (x) seconds with (x) queries
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- 15-01-2010, 15:12:31Üyeliği durduruldu
function db_query($sql) { // Declare as static variable before declare global static $total_mysql_queries; // Declare as global variable global $total_mysql_queries; if(mysql_query($sql)) { // Query successfully executed? // Add +1 to variable $total_mysql_queries ++$total_mysql_queries; // Return true, the query was successfully executed return true; } // I'm sure there was a mysql error... return false; } Include the db_query() function into your code, replacing all instances of mysql_query and perform your MySQL queries. db_query('SELECT `user` FROM `users` WHERE `id` = 1 ORDER BY `id` LIMIT 1;') or die(mysql_error()); db_query('SELECT `user` FROM `users` WHERE `id` = 2 ORDER BY `id` LIMIT 1;') or die(mysql_error()); db_query('SELECT `user` FROM `users` WHERE `id` = 3 ORDER BY `id` LIMIT 1;') or die(mysql_error()); Than, at the end of your code, add: echo 'A total of ', isset($total_mysql_queries) ? $total_mysql_queries : 0, ' MySQL queries were executed.'; - 15-01-2010, 16:34:05Bu sanırım belirli bir siteye özel hazırlanmış. Alttaki gibi bir hata alıyorum eklediğimde.
Parse error: syntax error, unexpected T_STRING in /home/user/public_html/oyun.php on line 40
Yani kısaca amacım sayfalarda harcanan query miktarlarını görmek, bunun başka bir yolu varsa o da olabilir. İllede sayfa altında göstermek değil amacım...