To calculate the K and τ values for the heating system, we can use the heat exchanger equation:
Q = K * (Ti - To) * e^(-t / τ)
where: Q is the heat transfer rate (in this case, it's the product of the mass flow rate and specific heat capacity), K is the system gain, Ti is the initial temperature of the heating water, To is the initial temperature of the waste water, t is the time, and τ is the time constant.
Given values: Ti = 45 °C To = 10 °C Flow rate of heating water (m1) = 25 m³/h Flow rate of waste water (m2) = 30 m³/h
First, let's calculate the heat transfer rate Q. We can assume that the specific heat capacity of water is 4.18 kJ/kg·°C.
Q = m2 * c * (To - Ti)
where c is the specific heat capacity of water.
Q = 30 * 10³ * 4.18 * (10 - 45) = -94.35 * 10⁶ kJ/h
a) Calculating K: K = Q / (m1 * (Ti - To))
K = (-94.35 * 10⁶) / (25 * (45 - 10)) = -4.19 * 10⁶ kJ/h·m³
b) Calculating τ: To find the value of τ, we need to determine the time it takes for the temperature of the waste water to reach 63.2% of its final value when the heating water temperature changes from 45 °C to 55 °C.
Using the exponential equation:
e^(-t / τ) = 0.632
Solving for t:
  • t / τ = ln(0.632)
t = - τ * ln(0.632)
We know that at t = 0, the temperature of the heating water changes to 55 °C.
Thus, the response equation for the output variable, y(t), is given by:
y(t) = To + (Ti - To) * (1 - e^(-t / τ))
At t = 0, Ti = 55 °C and To = 10 °C.
c) To find the outlet temperature of the waste water at 5 hours, we can substitute t = 5 into the response equation:
y(t = 5) = To + (Ti - To) * (1 - e^(-5 / τ))

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