<?php
                        $con=mysql_query("SELECT * FROM video WHERE='$radi' ORDER BY Rand() LIMIT 0,8");
                        while($rd=mysql_fetch_array($con)) {
                         echo'
                         <p><a href="'.video_link.'/'.$rd[video_radi].'.html"><img src="../video_resim/'.$rd[video_resim].$rd[video_uzanti].'" alt="'.$rd[video_adi].'" /><br />'.$rd[video_adi].'</a> </p>';
                         }
                         unset($con,$rd);
                          ?>

 						
Warning:  mysql_fetch_array(): supplied argument is not a valid  MySQL result resource in c:\appserv\www\soft\video\video\index.php  on line 142