<?php

$kayit = mysql_query("SELECT * FROM film order by id desc limit 0,10");
$result1 = mysql_query($kayit) or die (mysql_error());
while ($sozzz1 = mysql_fetch_assoc($result1))
{
echo $sozzz1["baslik"];
}
?>

bu şekil kullandım ama ; You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Resource id #5' at line 1

böyle hata verdi.