Arkadaslar en son bir hata veriyordu onuda duzeltebildim && yerine , kullanmam gerektigiymis UPDATE komutunu kullanirken kodun calisani asagida ...
Herkese Cok Tesekkur Ediyorum ..
Alıntı
<?php
include("inc/db.php");
$tempID = $_GET["tempID"];
$read = mysql_query("SELECT * FROM temp_content where temp_id='{$tempID}'");
$write = mysql_fetch_array($read);
$id = $write['temp_id'];
$name = $write['temp_name'];
$column = $write['temp_column'];
$system = $write['temp_system'];
$feature = $write['temp_feature'];
$image = $write['temp_image'];
$thumb = $write['temp_thumb'];
?>
<form action="<?php echo $_SERVER['REQUEST_URI']; ?>" method="POST">
<table>
<tr>
<td><input type="text" name="tp_id" value="<?php echo $tempID; ?>"></td>
<td><input type="text" name="tp_name" value="<?php echo $name; ?>"></td>
<td><input type="text" name="tp_column" value="<?php echo $column; ?>"></td>
<td><input type="text" name="tp_system" value="<?php echo $system; ?>"></td>
<td><input type="text" name="tp_thumb" value="<?php echo $thumb; ?>"></td>
<td><input type="text" name="tp_image" value="<?php echo $image; ?>"></td>
<td><input type="text" name="tp_feature" value="<?php echo $feature; ?>"></td>
<td><input type="submit" value="Submit" /></td>
</tr>
</table></form>
<?php
$edittemp = mysql_query("
UPDATE temp_content
SET temp_id = '{$_POST['tp_id']}',
temp_name = '{$_POST['tp_name']}',
temp_column = '{$_POST['tp_column']}',
temp_system = '{$_POST['tp_system']}',
temp_feature = '{$_POST['tp_feature']}',
temp_image = '{$_POST['tp_image']}',
temp_thumb = '{$_POST['tp_thumb']}'
WHERE temp_id = '{$tempID}'
");
if($edittemp) {
header("Location: index.php?admin=showtemp");
} else {
echo "AA";
}
?>